Q1. Two stations A and B are 110 kms apart on a straight line. One train starts from A at 7 a.m and travels towards B at 20km per hour speed Another train starts from B at 8 a.m. and travels towards A at a speed of 25 Km per hour at what time will they meet?

A.

B.

C.

D.

Suppose they meet x hrs after 7 a.m 

 

Distance covered by A in x hrs = (20 × x) 

 

Distance covered by B in (x-1) hrs = 25 (x -1) km. 

 

So they meet at 10 a.m.

Q2. A train running at certain speed crosses a stationary engine in 20 seconds. To find out the speed of the train. Which of the following information is necessary:

A.

B.

C.

D.

Since the sum of the lengths of the train and the length of the engine is needed, So both the lengths must be known.

Q3. A 120m long train takes 10 seconds to cross a man standing on a platform. The speed of the train is

A.

B.

C.

D.

Speed = (120/10) m/sec = 12 m/sec

Q4. The speed of a train 150m long is 50kmph. How much time will it take to pass a platform 600m long?

A.

B.

C.

D.

Speed =(50 x 5/18) m/sec = 125/9 m/sec 

 

Required Time = 54 sec

Q5. How much time will a train 171m long take to cross a bridge 229m long, if it is running at a speed of 45kmph?

A.

B.

C.

D.

Speed = 25/2 m/sec 

 

Required time = 32 sec

Q6. A train travelling at a speed of 30m/sec crosses a platform 600m long in 30seconds. The length of the train is

A.

B.

C.

D.

Let the length of the train be x m. 

 

Then it’s Speed = = 30 => 600 + x = 900 => x = 300m

Q7. A 130m long train crosses a bridge in 30 seconds at 45kmph. The length of the bridge is

A.

B.

C.

D.

Let the length of the bridge be x metres. 

 

Speed of the train = (130 + x) /30 * m/sec

130 + x  /30 = 25/2

 

 

But speed = (45 x 5/18) m/sec = 25/2 m/sec 

 

Therefore, => 130 + x = 375 => (375 -130) = 245m 

 

Hence, length of the bridge = 245m

Q8. A train travelling at constant speed crosses a 96m long platform in 12 seconds and another 141m long platform in 15 seconds. The length of the train and it’s speed are?

A.

B.

C.

D.

Let the length of the train be x metres. 

 

=> ( 96 + x ) / 12 = ( 141 + x ) / 15

 

=> 15x(96 +x) = 12 x (141 + x) 

 

=> 3x = (1692 -1440) = 252 

 

=> X = 84m 

 

Speed of the train = 15 m/sec 

 

 = (15 x 18/5)kmph = 54kmph

Q9. A train crosses a pole in 15 seconds while it crosses a 100m long platform in 25 seconds. The length of the train is

A.

B.

C.

D.

Let the length of the train be x meters. 

 

Then x/15 =  ( 100 + x ) / 25

 

=> 25x = 1500 + 15x 

 

=> 10x = 1500 

 

=> x =150. 

 

Hence the lengths of the trains is 150m

Q10. Two trains 105m and 90m long run at the speeds of 45 kmph and 72 kmph respectively in opposite direction on parallel tracks. The time which they take to cross each other is

A.

B.

C.

D.

Sum of the lengths of the trains = (105 + 90)m = 195m 

 

Relative speed = (72 +45)kmph 

 

= 117kmph =(117 x 5/18)m/sec = 585/18 m/sec 

 

Required Time = (195 x 18/585)sec = 6 Sec