Q 1 - √17161 =?
A. 129
B. 1198
C. 131
D. 141
√17161 = √(131 x 131) = 131
Q 2 - 176 + √2401 = ?
A. 14
B. 15
C. 18
D. 24
√176 +√2401 =√(176+49) =√225 =15
Q 3 - The square root of (1.44*0.81)/(0.9 * 3.6) is:
A. 0.6
B. 0.5
C. 1
D. 0.75
Given exp =(144*81/900*36) ⁱꜘ2 =12*9/30*6 =3/5 =0.6
Q 4 - √0.00059049 = ?
A. 0.243
B. 0.0243
C. 0.00243
D. 0.000243
given expression =√59049/100000000 = 243/10000 = 0.0243
Q 5 - The square root of (0.09+2 *0.21 +0.49) is
A. 0.58
B. 1
C. √21*1/5
D. None of these
(0.09+2*0.21+0.49)= (0.3)2+(0.7)2+2*0.3*0.7= (0.3+0.7)2=12=1 ∴√ 0.09 +2*0.21+0.49 = √1 = 1
Q 6 - (√225/729 - √25/144) / √16/81
A. 1/48
B. 5/48
C. 5/16
Now √225/729 = 5/9 , √25/144 = 5/12 and √16/81 = 4/9 ∴ given expression = (5/9-5/12)/4/9 = (20-15)/36 /4/9 = 5/36 /4/9 = (5/36*9/4) = 5/16
Q 7 - if √15 = 3.88, then what is the value of √5/3?
A. 1.29
B. 1.2934
C. 1.293
D. 1.295
√5/3 = √15*9= 3.88/3 =1.293
Q 8 - if 1120/ √ p =80 ,Then p =?
B. 140
C. 196
D. 225
1120/ √p= 80 ⇒ √p =1120/80 =14 ⇒ P=(14*14) = 196
Q 9 - if √2 = 1.4142, then the value of 7/(3+√2) is:
A. 1.5858
B. 4.4142
C. 3.4852
D. 3.5858
7/(3+√2)= 7/(3+√2)*(3-√2)/(3-√2) =7*(3-√2)/(9-2)=(3-√2) = (3-1.414)=1.58
Q 10 - 1250 oranges were distributed among a group of girls of a class. Each girls got twice as many oranges as the number of girls in that group . The number of the girls was :
A. 25
B. 45
C. 50
D. 100
let there be x girls in the group. Each girl got 2x oranges. ∴ 2x*x = 1250 ⇒ 2x2 =1250 ⇒ x2 =625 ⇒ x= √625 =25 Number of girls in the group= 25