Q1. A man purchases an electric heater whose printed price is 160 if he received two successive discounts of 20% and 10% he paid:

A.

B.

C.

D.

Price after 1st discount = 80% of Rs. 160 = Rs. 128 

 

Price after 2nd discount = 90% of Rs. 128 = Rs. 115.20 

Q2. Tarun bought a T.V with 20% discount on the labelled price. Had he bought it with 25% discount? He would have saved Rs. 500. At what price did he buy the T.V?

A.

B.

C.

D.

Labelled price be Rs. 100 

 

S.P in 1st case = Rs. 80 

 

S.P in 2nd case = Rs. 75 

 

Saving is Rs. 5 labelled price = Rs. 100 

 

Saving is Rs. 500 labelled price 

 

= Rs. (100/5 × 500) = Rs. 10000

Q3. The difference between a discount of 40% on Rs. 500 and two successive discount of 36% and 4% on the same amount is:

A.

B.

C.

D.

Sale after 40% discount = 60% of Rs. 500 = Rs. 300 

 

Price after 36% discount = 64% of Rs. 500 = Rs. 320

 

Price after next 4% discount = 96% of Rs. 320 = Rs. 307.20 

 

Difference in two prices = Rs. 7.20

Q4. A cloth merchant has announced 25% rebate in prices. If one needs to have a rebate of Rs. 40. Then how many shirts each costing Rs.32 he should purchase?

A.

B.

C.

D.

The number of shirts = X 

 

 Rebate = (25/100 × 32 X) = 8X 

 

 8X = 40 or X = 5

Q5. A dealer marks his goods 20% above cost price. He then allows some discount on it and makes a profit of 8%. The rate of discount is:

A.

B.

C.

D.

C.P = Rs. 100 

 

Marked Price = Rs. 120, 

 

S.P = Rs. 108 

 

Discount = (12/120 × 100)% = 10%

Q6. On selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. The cost price of a ball is:

A.

B.

C.

D.

NO Solution

Q7. Bhajan Singh purchased 120 reams of paper at Rs. 80 per ream. He spent Rs. 280 on transportation. Paid octrai at the rate of 40 paise per ream and paid Rs. 72 to the coolie. If he wants to have a gain of 8 %. What must be the selling price per ream?

A.

B.

C.

D.

C.P of 120 reams = Rs. (120 × 80 + 280 + 72 + 120 × 40) = Rs. 10000 

 

 C.P of 1 ream = (10000/120) = Rs. (250/3) 

 

 S.P of 1 ream = Rs. (108/100 × 250/3) = Rs. 90

Q8. A man sells a car to his friend at 10 % loss. If the friend sells it for Rs. 54000 and gains 20 %. The original C.P of the car was:

A.

B.

C.

D.

S.P = Rs. 54000, 

 

Gain earned = 20% 

 

 C.P = Rs. (100/120 × 54000) = Rs. 45000 

 

 S.P = Rs. 45000 and loss = 10% 

 

 C.P = Rs. (100/90 × 45000) = Rs. 50000

Q9. The cost price of an article which on being sold at a gain of 12 % yields Rs. 6 more than when it is sold at a loss of 12 % is:

A.

B.

C.

D.

NO Solution

Q10. A person bought an article and sold it at a loss of 10 % if he had bought it for 20 % less and sold it for Rs. 55 more he would have had a profit of 40 %. The C.P of the article is:

A.

B.

C.

D.

C.P = Rs. X 

 

 S.P = Rs. (90/100 × X) = Rs. (9/10 X) 

 

 C.P = Rs. (80/100 × X) = Rs. (4X/5) Gain = 40% 

 

 New S.P = Rs. (140/100 × 4X/5) 

 

 = Rs. (28/25 X) 28/25 X – 9/10 X = 55 or X = 250